### Example (strxfrm -- Transform String)

This example uses strxfrm to transform two different strings that have the same collating weight. It then calls strcmp to compare the new strings.

    #include <stdlib.h>
    #include <stdio.h>
    #include <locale.h>
    #include <string.h>

    #if (1 == __TOS_OS2__)
       #define LOCNAME "da_dk.ibm-865"      /* OS/2 name */
       char *string1 = "str\xA0ng1a";
       char *string2 = "strang1\x83";
    #else
       #define LOCNAME "da_dk.ibm-1252"  /* Windows name */
       char *string1 = "str\xE0ng1a";
       char *string2 = "strang1\xE2";
    #endif

    int main(void)
    {
       char *newstring1, *newstring2;
       size_t length1, length2, pw1, pw2;

       if (NULL == setlocale(LC_ALL, LOCNAME)) {
          printf("Locale \"%s\" could not be loaded\n", LOCNAME);
          exit(1);
       }
       length1 = strxfrm(NULL, string1, 0);
       pw1 = strlen(string1);
       length2 = strxfrm(NULL, string2, 0);
       pw2 = strlen(string2);
       if (NULL == (newstring1 =(char*) calloc(length1 + 1, 1)) ||
           NULL == (newstring2 =(char*) calloc(length2 + 1, 1))) {
          printf("insufficient memory\n");
          exit(1);
       }

       /* Get primary weight of each string */
       if ((strxfrm(newstring1, string1, pw1 + 1) != length1) ||
           (strxfrm(newstring2, string2, pw2 + 1) != length2)) {
          printf("error in string processing\n");
          exit(1);
       }
       if (0 != strcmp(newstring1, newstring2))
          printf("wrong results\n");
       else
          printf("correct results\n");
       return 0;

       /**********************************************************
          The output should be similar to :

          correct results
       **********************************************************/
    }